Matched: the best known value

Packing 41 unit squares in a square

What is the smallest square that holds 41 squares of side 1, without overlap? The best known answer is a side of 6.9266930945, from Thomas Schadt, optimized by David Ellsworth, 2026. Velmar Cut matched it.

41 squares in a square of side 6.9266930945, 26 upright and 15 turned

The numbers

Best known side6.9266930945
Best known side, in full6.9266930944688
Side from Velmar Cut6.9266930945
Side from Velmar Cut, in full6.926693094470345
Difference, Velmar Cut minus best known+1.545E-12
Found byThomas Schadt, optimized by David Ellsworth, 2026
StatusBest known, not proved
Time to reach it1660.447 s in all, several runs
Threads used4 or more
MachineIntel Core i5-12600K, 10 cores, 16 threads
Squares26 upright, 15 turned
A plain grid needsside 7

The time to reach this result on one desktop PC.

The problem at 41 squares

Five squares more than a grid of side 6 holds, so a plain grid needs side 7. The source table gives the best known side as a root of a polynomial of degree 42, far longer than at 28 or 39. This layout has twenty-six upright squares and fifteen turned.

A plain grid: side 7

41 upright squares in rows inside a square of side 7
In upright rows, 41 squares need side 7.

Best known: side 6.9266930945

41 squares in a square of side 6.9266930945, 26 upright and 15 turned
Velmar Cut's layout, at the best known side from Thomas Schadt, optimized by David Ellsworth, 2026.

Blue squares stand upright, orange squares are turned. Both pictures are at the same scale.

History

The best known value at this size is the result of Thomas Schadt, optimized by David Ellsworth, 2026, and it is their result that Velmar Cut equals.

The source table lists no proof that this side is optimal: Friedman's 2009 survey gives 6.4061 as the best lower bound (Trevor Green), so a smaller square may still exist.

Thomas Schadt found this packing in December 2025 with a program he wrote himself. David Ellsworth refound and refined it around the turn of the year and optimized it in January 2026. Erich Friedman's 2009 survey notes that Charles F. Cottingham's packing of 1979 was only improved in 2005, by David W. Cantrell.

When Side Who What happened
1979 2 + (7/2)√2 ≈ 6.94975 Charles F. Cottingham found
early 1980 11/3 + (7/3)√2 ≈ 6.96650 Evert Stenlund did not improve
October 2005 ≈ 6.94725 David W. Cantrell improved
April 2014 ≈ 6.93787 Joe DeVincentis improved
November 2024 ≈ 6.94614 David Ellsworth did not improve on the best known value
December 2025 ≈ 6.93669 Thomas Schadt improved
December 2025 ≈ 6.93667 David Ellsworth optimized
December 2025 ≈ 6.92694 Thomas Schadt improved
December 2025 to January 2026 ≈ 6.92670 David Ellsworth refound and refined
January 2026 ≈ 6.92669 David Ellsworth optimized, best known today

Sources

The best known values come from "Squares in Squares", David Ellsworth, from the original by Erich Friedman.

Each size names who holds its value and since when. It is their result that Velmar Cut equals.

Is the packing valid?

Yes. The certificate passes the exact check: 41 pieces, each exactly a unit square, each inside the box, no two overlapping.

How close is it to the best known value?

The side from Velmar Cut minus the best known value is +1.545E-12, within the rule's 1E-11.

A match: the certificate passes the exact check, and |L - best known| <= 1E-11, the difference published unrounded for each size. L is the side of the certificate's box, rounded up at 15 decimals.

You don't have to trust us

With plain Python and no other software, verify_exact.py beside the certificate checks the file above by exact arithmetic, with no rounding.

python verify_exact.py 41-squares-in-a-square.csv --squares=41 --reference=6.9266930944688 --epsilon=1e-11

It does not prove that the packing is optimal, that the reference is the current best known value, or how the layout was found.

The full check and what it covers

Free trial

Seven days with every edition

Install Velmar Cut, enter the parts and stock of a current job and print the cutting schedule. The trial starts on first run and needs no account or card.